A United States Air Force plane has issued what seems to be an emergency squawk in the area over Stansted Airport.
A squawk 7700/7600/7500 was detected in the area by the Boeing aircraft,
The codes are transmitted in the event of an emergency.
7700 means there is an emergency, 7600 refers to a communications failure, and 7500 refers to unlawful interference.
The aircraft is LGR89 62-3540, a Boeing KC-135R.
It was detected at approximately 2,029 feet, according to @LondonFIRinfo on Twitter, which tracks notable flight movements across the London region.
More information regarding the emergency is expected
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